Law of Sines Solving Angle Side Angle

 

          This week we are showing you how to find the missing angle and sides of a triangle when you have two angles and a side.  This method is used to find distance.

Teaser: Raspune has an enemy ship in his sights and is finding its exact distance.  Two sensors on his ship are arranged on a baseline of 30 meters (g).  One sensor finds and angle of 50 degrees (a) and the other registers 44 degrees (b).  Find the missing parts of the triangle and average a and b to find the correct distance.

 

 

sin a/a = sin b/b = sin g/c

 

 

 

 

The ratio of the sine of an angle to its opposite side is the same as the ratio of the sine of either of the other angles to its opposite side.

 

*

 

Example :  If b = 43o, g = 36o, and a = 90 cm, find a, b, and c.

 

                   a + b + g = 180o

                   The sum of the angles of a given triangle is 180o.

                   a + 43o + 36o = 180o

                   b = 43o and g = 36o

                   a + 79o = 180o

                   Add 43 and 36

                   a + 79o – 79o = 180o – 79o

                   Subtract 79 from both sides of the equation.

                   a = 101o

                   Subtract 79 from a and Subtract 79 from 180

                   sin a/a = sin /b

                   Law of sines

                   sin 101o/90 cm = sin 43o/ b

                    b = 43o, a = 90 cm and a = 101o

                   90b cm(sin 101o/90 cm) = 90b cm(sin 43o/ b)

                   Multiply both side of the equation by 90b cm

                   b(sin 101o) = 90 cm(sin 43o)

                   90b cm times sin 101o/90 cm and 90b cm times sin 43o

                   (b(sin 101o))/ (sin 101o) = (90 cm(sin 43o))/ (sin 101o)

                   Divide both sides of equation by sin 101o

                   b = (90 cm(sin 43o))/ (sin 101o)

                   Divide b(sin 101o) by sin 101o and 90 cm(sin 43o) by sin 101o

                   b = (90 cm (.6820))/.9816

                   sin 43o = .6820 and sin 101o = .9816

                   b = 62.5 cm

                   Perform indicated operations

                   sin a/a = sin g/c

                   Law of sines

                   sin 101o/90 cm = sin 36o/ c

                    g = 36o, a = 90 cm and a = 101o

                   90c cm(sin 101o/90 cm) = 90c cm(sin 36o/ c)

                   Multiply both side of the equation by 90b cm

                   c(sin 101o) = 90 cm(sin 36o)

                   90c cm times sin 101o/90 cm and 90c cm times sin 36o

                   (c(sin 101o))/ (sin 101o) = (90 cm(sin 36o))/ (sin 101o)

                   Divide both sides of equation by sin 101o

                   c = (90 cm(sin 36o))/ (sin 101o)

                   Divide c(sin 101o) by sin 101o and 90 cm(sin 36o) by sin 101o

                   c = (90 cm (.5878))/.9816

                   sin 43o = .5878 and sin 101o = .9816

                   c = 53.9 cm

                   Perform indicated operations

         

 Problems

1) If b = 27.5o, g = 54.5o, and a = 9.27 mm, find a, b, and c.

 

2) If b = 12.67o, g = 100o, and a = 17.3 km, find a, b, and c.

 

 

 

 



* Note: Triangle does not coincide with actual proportions.  We are sorry for this inconvinience.